pressuredrop=1.55E4/1E3 (19.8mmHg)
solve that.
BP=100 - .05*pressure drop
What is the boiling point of water at an elevation of 1.55×10^4 ft ?
The atmospheric pressure at sea level is 760mmHg . This pressure decreases by 19.8mmHg for every 1000-ft increase in elevation.
The boiling point of water decreases 0.05 degrees celsius for every 1mmHg drop in atmospheric pressure.
1 answer