Asked by Kay
After solving a difficult physics problem, an excited student throws his book straight up. It leaves his hand at 2.5 m/s from 1.5 m above the ground.
A) How much time does it take until the book hits the floor?
B) What's its velocity then?
A) How much time does it take until the book hits the floor?
B) What's its velocity then?
Answers
Answered by
Damon
h = 1.5 + 2.5 t -4.9 t^2
when is h = 0?
solve quadratic for t
4.9 t^2 -2.5 t - 1.5 = 0
you could use http://www.math.com/students/calculators/source/quadratic.htm
Note, quadratics have two solutions of course. In this problem if you get a neagative time, that is how long ago it could have passed the floor on the way up :)
v = Vi - 9.81 t = 2.5 -9.81 t
it better be negative because it is headed down when it hits the floor :)
when is h = 0?
solve quadratic for t
4.9 t^2 -2.5 t - 1.5 = 0
you could use http://www.math.com/students/calculators/source/quadratic.htm
Note, quadratics have two solutions of course. In this problem if you get a neagative time, that is how long ago it could have passed the floor on the way up :)
v = Vi - 9.81 t = 2.5 -9.81 t
it better be negative because it is headed down when it hits the floor :)
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