In 2 seconds, it will fall a distance (1/2)gt^2 = 19.6 m. It will not have hit the ground yet. You can ignore the h = 60 m
The speed will have reached a value
V = gt = 19.6 m/s
The KINETIC energy will have increased by (1/2) m (19.6)^2 . If you include potential energy, there will be no change.
Hi, I have a question for physics
An object with mass m = 20 kg is released from a height h = 60 m above the ground. After 2 seconds, the object's quantity of energy
Thanks for your help
mvh
Oddbjørn
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1 answer