Asked by Realone
An aeroplane leaves the point X (43°N,71°W) and flies due east at 500km/h.After 3hours (a)how far has it travelled (b)what is its longitude?
Answers
Answered by
MathMate
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Answered by
Butter Priye
A. Speed= distance/time
: Distance=speed × time
= 500 × 3
= 1500kmhr
B. Circumference of latitude=2πr
Where r = RCOS(lat)
= 2×22/7×6400×cos43°
= 281600×0.731354
=29,421.33km
To find the longitude
1500/29421.33 × 360=18.4°
Longitude=71° - 18.4 =52.6°
: Distance=speed × time
= 500 × 3
= 1500kmhr
B. Circumference of latitude=2πr
Where r = RCOS(lat)
= 2×22/7×6400×cos43°
= 281600×0.731354
=29,421.33km
To find the longitude
1500/29421.33 × 360=18.4°
Longitude=71° - 18.4 =52.6°
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