Asked by Sherlique
Hello,
If I add water to a solid, how do i represent it in a equation with phases?
for example the NaNO3 was the solid in this case and H2O was the liquid,
does NaNO3 turns into an aqueous or stays as solid when I write the equation?
Which one would be correct?
1) NaNO3(s) + H2O(l) = HNO3(aq) + NaOH(aq)
or
2)NaNO3(aq) + H2O(l) = HNO3(aq) + NaOH(aq)
Thanks!
If I add water to a solid, how do i represent it in a equation with phases?
for example the NaNO3 was the solid in this case and H2O was the liquid,
does NaNO3 turns into an aqueous or stays as solid when I write the equation?
Which one would be correct?
1) NaNO3(s) + H2O(l) = HNO3(aq) + NaOH(aq)
or
2)NaNO3(aq) + H2O(l) = HNO3(aq) + NaOH(aq)
Thanks!
Answers
Answered by
bobpursley
it is in aq phase when it reacts:
NaNO3(aq)+...
NaNO3(aq)+...
Answered by
Sherlique
I don't understand how it turns into aq when its a solid I add into the water, isn't only the products turn into aq?
Answered by
bobpursley
nope, once dissolved, it is in aqueous solution.
Answered by
Sherlique
So despite having to shake the test tube for it to dissolve into the water, NaNO3 in this case would be considered as Aqueous?
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