Asked by Ainsley
How many mL of water would you add to 32 mL of 0.62 M ammonium chloride stock solution to make a 0.3 M solution?
Answers
Answered by
DrBob222
0.62 M x (32/x) = 0.3 M
x = total voume so x-32 will be how much you must add.
x = total voume so x-32 will be how much you must add.
Answered by
Damon
I would have .62 mols in a liter
so I have .62 (.032 ) = .01984 mols
.01984 mols /x liters = 0.3 mols/1 liter
x = .01984/.3 = .06613 liters = 66.13 mL
so add 66 -32 = 34 mL of water
so I have .62 (.032 ) = .01984 mols
.01984 mols /x liters = 0.3 mols/1 liter
x = .01984/.3 = .06613 liters = 66.13 mL
so add 66 -32 = 34 mL of water
Answered by
bobpursley
How many mL of water would you add to 32 mL of 0.62 M ammonium chloride stock solution to make a 0.3 M solution? >>
Another method. You are diluting it .62/.3 = 2.06 times. That means one part original, and then add 1.06 parts water.
if one part is 32ml, then 1.06 parts is 33.9 ml of water
Another method. You are diluting it .62/.3 = 2.06 times. That means one part original, and then add 1.06 parts water.
if one part is 32ml, then 1.06 parts is 33.9 ml of water
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