Asked by lis
                find the area of the region bounded by the curves f(x)=x-x^3 ; g(x)=x^2-x  ; over [0,1]
            
            
        Answers
                    Answered by
            Steve
            
    since f > g on (0,1), the area is just
∫[0,1] (x-x^3)-(x^2-x) dx = 5/12
    
∫[0,1] (x-x^3)-(x^2-x) dx = 5/12
                    Answered by
            lis
            
    ty!
    
                    Answered by
            lis
            
    i got 5/6?
    
                    Answered by
            lis
            
    i used the equation 2x-x^5, is that wrong?
    
                    Answered by
            Steve
            
    it sure is
(x-x^3)-(x^2-x) = -x^3-x^2+2x
You can't combine x^2 and x^3 to make x^5!! They're added, not multiplied.
    
(x-x^3)-(x^2-x) = -x^3-x^2+2x
You can't combine x^2 and x^3 to make x^5!! They're added, not multiplied.
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