Asked by lis

find the area of the region bounded by the curves f(x)=x-x^3 ; g(x)=x^2-x ; over [0,1]
Answered by Steve
since f > g on (0,1), the area is just

∫[0,1] (x-x^3)-(x^2-x) dx = 5/12
Answered by lis
ty!
Answered by lis
i got 5/6?
Answered by lis
i used the equation 2x-x^5, is that wrong?
Answered by Steve
it sure is

(x-x^3)-(x^2-x) = -x^3-x^2+2x

You can't combine x^2 and x^3 to make x^5!! They're added, not multiplied.
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