Ask a New Question

Asked by lis

find the area of the region bounded by the curves f(x)=x-x^3 ; g(x)=x^2-x ; over [0,1]
8 years ago

Answers

Answered by Steve
since f > g on (0,1), the area is just

∫[0,1] (x-x^3)-(x^2-x) dx = 5/12
8 years ago
Answered by lis
ty!
8 years ago
Answered by lis
i got 5/6?
8 years ago
Answered by lis
i used the equation 2x-x^5, is that wrong?
8 years ago
Answered by Steve
it sure is

(x-x^3)-(x^2-x) = -x^3-x^2+2x

You can't combine x^2 and x^3 to make x^5!! They're added, not multiplied.
8 years ago

Related Questions

Find the area of the region between the curves y=lnx and y=ln2x from x=1 and x=5. a) Find the area of the region R bounded by the graphs of the equations y=2x−x^2, x=0, and y=0. b... Find the area of the region that lies inside the first curve and outside the second curve. r = 1 +... Find the area of the region RR bounded by y=sin(x), y=cos(x), x=−π/3, x=13/6. Find the area of the region bounded by the curves y = x^2 - 1 and y = cos(x). I've tried doing this... find the area of the region Find the area of region between the graph of y=x^2+4x+3 and y=x^2 between the intervals x=1 and x=3 Find the area of the region enclosed by the graph of the equation $x^2-14x+3y+70=15+9y-y^2$ that lie... Find the area of the region enclosed between and from to . Hint: Notice that this region consists...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use