Asked by Ethan
4Fe + 3O2 = 2Fe2O3
158g of Fe will react with how many litres of O2 to produce the maximum amount of Fe2O3
158g of Fe will react with how many litres of O2 to produce the maximum amount of Fe2O3
Answers
Answered by
DrBob222
mols Fe ==> grams/molar mass = ?
Convert to mols O2. That's ?mols Fe x (3 mols O2/4 mols Fe) = ?
Then mols O2 x 22.4 L/mol = L O2
Convert to mols O2. That's ?mols Fe x (3 mols O2/4 mols Fe) = ?
Then mols O2 x 22.4 L/mol = L O2
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