Asked by baehji
4FeS (s) + 7O2 (g) --> 2Fe2O3 (s) + 4SO2 (g)
Entropy value for iron (II) sulfide is 67 J/K mol
I don't understand how to find entropy
Entropy value for iron (II) sulfide is 67 J/K mol
I don't understand how to find entropy
Answers
Answered by
DrBob222
Do you want the entropy of the reaction?
dSrxn = (n*dSo products) - (n*dSo reactants).
Look up the standard S values in your text/notes and plug into the above equation and solve for dSrxn.
dSrxn = (n*dSo products) - (n*dSo reactants).
Look up the standard S values in your text/notes and plug into the above equation and solve for dSrxn.
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