Asked by Anonymous
can you check my work
Given: r = 4/-2-6sintheta
What is the eccentricity of the function?
r = 4/-2-6sintheta
r=4/8sin theta
r=2sintheta
the eccentricity is 2
Given: r = 4/-2-6sintheta
What is the eccentricity of the function?
r = 4/-2-6sintheta
r=4/8sin theta
r=2sintheta
the eccentricity is 2
Answers
Answered by
Steve
nope.
The standard form for a conic is
r = ep/(1 ± e sinθ)
try again
The standard form for a conic is
r = ep/(1 ± e sinθ)
try again
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