Asked by Anonymous

can you check my work

Given: r = 4/-2-6sintheta

What is the eccentricity of the function?

r = 4/-2-6sintheta
r=4/8sin theta
r=2sintheta

the eccentricity is 2
Answered by Steve
nope.

The standard form for a conic is

r = ep/(1 ± e sinθ)

try again