Question
You exert a force of 200 N at an angle of 15 degrees above horizontal to pull a 10 kg box across the floor at constant velocity. If the coefficient of kinetic friction between the box and the floor is 0.42, what is the acceleration of the box?
Answers
bobpursley
some of the force is reducing weight W.
net force=mass*acceleration
200cos15-mu*W=m*acceleration
200cos15-mu*(mg-200sin15)=m*a
solve for acceleration a.
net force=mass*acceleration
200cos15-mu*W=m*acceleration
200cos15-mu*(mg-200sin15)=m*a
solve for acceleration a.