Asked by Anonymous
You exert a horizontal force of 200 N to pull a 10-kg box across the floor. If the coefficient of kinetic friction between the box and the floor is .42, what is the acceleration of the box?
Answers
Answered by
Damon
friction force = 10*9.81*.42 = 41.2N
net force = 200 - 41.2 = 158.8 N
a = 158.8 / 10 = 15.9 m/s^2
net force = 200 - 41.2 = 158.8 N
a = 158.8 / 10 = 15.9 m/s^2
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