Asked by Harra
A stone is dropped into a still pond sends out a circular ripple whose radius increases at a constant rate of 2 meters per second. How rapidly is the area enclosed by the ripple increasing at the end of 20 seconds?
Answers
Answered by
Damon
hint
dA = 2 pi r dr so dA/dr = 2 pi r
and
dA/dt = dA/dr * dr/dt
dA = 2 pi r dr so dA/dr = 2 pi r
and
dA/dt = dA/dr * dr/dt
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