Question

A car of weight 1.4*10^4N is moving up an incline at a constant speed of 6.2 m/s . The incline makes an angle of 5.0 to the horizontal. A frictional force of 600 N acts on the car in opposite direction. State the net force of the car

Answer 1

If it is going up at constant speed, then
pushing force-gravityforce-friction=0

pushing force=mgSinTheta+600N

That is the <u> net pushing force on the car</u>