Asked by Universal Gravitation
What would be the weight of a 1.0kg mass on the surface of Mars? The mass of Mars is 0.11 that of the earth, and its radius is 0.53 that of the earth.
Answers
Answered by
Damon
F = m (G M/r^2 )
Fearth = 1 (G Me/re^2) = 1 * 9.81
so for earth (G Me/r^2) = 9.81
Fmars = 1 ( G Mmars/rmars^2)
= 1 (G .11 Me/ .53^2 re^2)
= 1 (.11/(.53)^2) (G Me/re^2)
= 1 (.392) (9.81) = 3.84 Newtons
Fearth = 1 (G Me/re^2) = 1 * 9.81
so for earth (G Me/r^2) = 9.81
Fmars = 1 ( G Mmars/rmars^2)
= 1 (G .11 Me/ .53^2 re^2)
= 1 (.11/(.53)^2) (G Me/re^2)
= 1 (.392) (9.81) = 3.84 Newtons
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