Question
Find the area of the region in the first quadrant between the curves y=x^8, and y=2x^2-x^4
Answers
Steve
what's the trouble? The height of each small rectangle is just the distance between the curves, so
a = ∫[0,1] (2x^2-x^4) - (x^8) dx
a = ∫[0,1] (2x^2-x^4) - (x^8) dx