Asked by Anon
Find the area of the region in the first quadrant between the curves y=x^8, and y=2x^2-x^4
Answers
Answered by
Steve
what's the trouble? The height of each small rectangle is just the distance between the curves, so
a = ∫[0,1] (2x^2-x^4) - (x^8) dx
a = ∫[0,1] (2x^2-x^4) - (x^8) dx
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