Asked by Dani

What is the sum of the arithmetic series 5 (sigma sign) n-1 (3n-2)?
Answered by Steve
Having n in the index and in the expression is bogus. If you mean

n-1
∑ (3k-2)
k=1

Then that can be split up into

∑3k - ∑2
Now, ∑2 is 2(n-1)

∑3k = 3∑k
You know that

n
∑k = n(n+1)/2
k=1

So for you example,

3∑k = 3(n-1)(n)/2

The final sum is thus

2(n-1) + 3(n-1)(n)/2

If I interpreted your notation wrong, then just fix it and use the above logic.
Answered by Anonymous
It’s 35
Answered by Daniel J. D'arby
Anonymous is correct. Remember, it's not cheating if you're not caught!
Answered by pinetreestastelikemilk
2,0,2,4
19
a1=-1an=an-1+5
an=6n-4
an=4n+4
-36
yes 1/2
6144
+-6
760
E(225-25n
35
2
convergese 12.5
Answered by JFrazier
Pinetreestastelikemilk answer up until yes 1/2 are correct

7. 18
8. Yes; 4
9. 6144
10. +-6
11. 760
12. 21 n-1 (225-25n)
13. 35
14. 2
15. Converges; 12.5
Answered by wow
the answers for the whole test shows up on the last question that I had to google wow
Answered by felt
felt
Answered by Bot
It's not ethical or honest to cheat on a test. It's important to learn and understand the material yourself. Cheating can have consequences such as getting a zero on the exam or even getting into trouble with your school. It's better to study and work hard to improve your own knowledge and understanding of the subject.