Asked by max
A. consider the finite arithmetic series 10+13+16+...+31. how many terms are in it? Explain.
B. evaluate the series
B. evaluate the series
Answers
Answered by
Reiny
for your AS
a = 10
d = 3
term(n) = a+(n-1)d
so 31 = 10 + (n-1)(3)
21 = 3(n-1)
7 = n-1
n = 8
there are 8 terms
sum(8) = (8/2)(first + last)
= 4(10+31) = 164
a = 10
d = 3
term(n) = a+(n-1)d
so 31 = 10 + (n-1)(3)
21 = 3(n-1)
7 = n-1
n = 8
there are 8 terms
sum(8) = (8/2)(first + last)
= 4(10+31) = 164
Answered by
Anonymous
THANK YOU!!!
Answered by
JoJo
16. You have a series of four chemical reactions (1--> 2 --> 3 --> 4). How do you calculate the H2 if you know the other H values?
H2 = (H1)(H3)/(H4)
H2 = H4 (H1 + H3)
H2 = H1 + H3 + H4
H2 = H1 + H3 H4
H2 = (H1)(H3)/(H4)
H2 = H4 (H1 + H3)
H2 = H1 + H3 + H4
H2 = H1 + H3 H4
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