Asked by Olayisiye tesli
The fifth term of an arithmetic progression is three times the first term. Find the sum of the progression given that a quater of the fifth term is 9
Answers
Answered by
oobleck
a+4d = 3a
(a+4d)/4 = 9
so clearly 3a=36, so a=12, making d=6
APs have no end, so there is no sum.
(a+4d)/4 = 9
so clearly 3a=36, so a=12, making d=6
APs have no end, so there is no sum.
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