Asked by Akheel a

A ball thrown vertically from the top of a building 96m at initial velocity 80m/sec.the distance 's' of the ball of the ground after 't' second is s=96+80t-4.5t^2. After how many seconds does the ball strike the ground...?

Answers

Answered by Steve
see related questions below
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions