Asked by Muhammad
Determine the relative extremum for the function ,
f(x,y)=((x^2)+(y^2))(e^-x)
f(x,y)=((x^2)+(y^2))(e^-x)
Answers
Answered by
Steve
df/dx = e^-x (x^2-2x+y^2)
df/dy = 2e^-x y
both are zero only at (0,0)
df/dy = 2e^-x y
both are zero only at (0,0)
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