Asked by Liz
relative maxima and relative minima
2x^2+ 4000/x +10
2x^2+ 4000/x +10
Answers
Answered by
Steve
y' = 2(x^2+20x-2000)/(x+10)^2
so, we just need to find where
x^2+20x-2000 = 0
so, we just need to find where
x^2+20x-2000 = 0
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