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Asked by Liz

relative maxima and relative minima
2x^2+ 4000/x +10
12 years ago

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Answered by Steve
y' = 2(x^2+20x-2000)/(x+10)^2
so, we just need to find where

x^2+20x-2000 = 0
12 years ago
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relative maxima and relative minima
2x^2+ 4000/x +10

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