Question
relative maxima and relative minima
2x^2+ 4000/x +10
2x^2+ 4000/x +10
Answers
Steve
y' = 2(x^2+20x-2000)/(x+10)^2
so, we just need to find where
x^2+20x-2000 = 0
so, we just need to find where
x^2+20x-2000 = 0