Asked by Tejika Bajaj
A 5kg ball is dropped from a height of 10m
a) find the initial potential energy of the ball
B. Find the kinetic energy of the ball just before it reaches ground.
C. Calculate the velocity before it reaches the ground.
a) find the initial potential energy of the ball
B. Find the kinetic energy of the ball just before it reaches ground.
C. Calculate the velocity before it reaches the ground.
Answers
Answered by
Kim
I can help you with C:
You have height, acceleration (9.81), and initial velocity (0) so you use:
Vf ^2 = Vi^2 + 2gh
You have height, acceleration (9.81), and initial velocity (0) so you use:
Vf ^2 = Vi^2 + 2gh
Answered by
Henry
B. PE = M*g*h Joules.
B. KE = PE =
C. V^2 = Vo^2 + 2g*h = 0 + 19.6*10 = 196, V = 14 m/s.
B. KE = PE =
C. V^2 = Vo^2 + 2g*h = 0 + 19.6*10 = 196, V = 14 m/s.
Answered by
Henry
Correction:
A. PE = M*g*h Joules.
A. PE = M*g*h Joules.
Answered by
nandini
a) potential energy=mgh =5*9.8*10=490j b)kinetic energy=1/2mv^2=0 hope it help
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