Asked by Anonymous
In a vertical lifting an object with mass of 2kg is lifted 1m above the ground. A work of 80J is done with a constant force. What is the acceleration of the object?
Answers
Answered by
Henry
Fap = Force applied.
Fap*d = 80 J.
Fap*1 = 80, Fap = 80 N.
Fap = M*a. a = Fap/M. = 80/2 = 40 m/s^2.
Fap*d = 80 J.
Fap*1 = 80, Fap = 80 N.
Fap = M*a. a = Fap/M. = 80/2 = 40 m/s^2.
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