Question

An object is projected vertically upwards and returns to the point of projection 12s later. Ignore air resistance and determine the velocity with which it was projected?

Answer 1

Vf=Vi +at
Vf=0, Vi=?, a=-9.8 remeber time taken to go up is equal to the time taken to go back to the point of projectile.. THEREFORE t=6

Vf=Vi +at
(0)=Vi +(-9.8)(6)
Vi=58.8m/s

***[OR]***

Vf=Vi +at
Vf=-Vi, Vi=?, a=-9.8, t=12
(-Vi)=Vi +(-9.8)(12)
-2Vi= -117.6
Vi=58.8m/s

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Answer 2

It corect