Asked by Thakgalo sakwana

An object is projected vertically upwards and returns to the point of projection 12s later. Ignore air resistance and determine the velocity with which it was projected?

Answers

Answered by Thakgalo sakwana
Vf=Vi +at
Vf=0, Vi=?, a=-9.8 remeber time taken to go up is equal to the time taken to go back to the point of projectile.. THEREFORE t=6

Vf=Vi +at
(0)=Vi +(-9.8)(6)
Vi=58.8m/s

***[OR]***

Vf=Vi +at
Vf=-Vi, Vi=?, a=-9.8, t=12
(-Vi)=Vi +(-9.8)(12)
-2Vi= -117.6
Vi=58.8m/s

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Answered by Erick
It corect
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