An object is projected vertically upwards with a velocity of 28m/s. Two seconds later, another object is thrown vertically upwards with a velocity of 32 m/s. When and where will the two objects meet?

Answer 1

Think about it.

In 2 seconds, the first object, traveling at 28m/s, is 56m high

Once the second object is thrown up at the speed of 32m/s, it will close in on the first object at the net speed of 32 - 28 = 4m/s.

You can now determine the time it takes for the second object to catch up to the first object and how far they have traveled.

Answer 2

But you don't know at how many seconds the first object is projected upwards! Wouldn't you sub in those motion formulas for this type of question?