Asked by Joshua

I need help with this question. What should be the cell potential if the [Cu2+] is 1.0 x 10-5 mol/L?

please help
Answered by DrBob222
I suppose you mean the half cell potential.
E = Eo - (0.0592/n)Log(red/ox)
Cu^+2 + 2e ==> Cu
Cu is reduced form.
Cu^+2 is oxidized form.
Plug into the above equation and solve for E. This is E for the concn given as well as for T = 25 C.
Answered by Stefan
42...
It's always 42
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