Question
1.13g plastic stopper is attached to a 0.93-m string. The stopper is swung in a horizontal circle, making one revolution in 1.18s(period T). Find the tension force(equivalent to the centripetal force)exerted by the string on the stopper? (V=2(pie)r/T)?
2. A football is thrown at 30 m/s(speed of release Vi)is 30 m/s, and its angle of release is 40 degree with respect to the horizontal. What is its horizontal velocity Vix? And what is its vertical velocity Viy? (Using trigonometry)
3. In a long jumper's motion, the highest point of the trajectory Y is 1.8m, the horizontal velocity at this point Vx is 7.2m/s. What is the full range of this long jump motion?(notice that the trajectory for this motion is symmetrial)
4. A car traveling at 30 m/s lost control and fell off a 50-m cliff by a projectile trajectory into a flat valley. Where should the car land on the flat bottom of the valley?
(( Note I was absent but my teacher couldn't explain anything to me so help please?))
2. A football is thrown at 30 m/s(speed of release Vi)is 30 m/s, and its angle of release is 40 degree with respect to the horizontal. What is its horizontal velocity Vix? And what is its vertical velocity Viy? (Using trigonometry)
3. In a long jumper's motion, the highest point of the trajectory Y is 1.8m, the horizontal velocity at this point Vx is 7.2m/s. What is the full range of this long jump motion?(notice that the trajectory for this motion is symmetrial)
4. A car traveling at 30 m/s lost control and fell off a 50-m cliff by a projectile trajectory into a flat valley. Where should the car land on the flat bottom of the valley?
(( Note I was absent but my teacher couldn't explain anything to me so help please?))
Answers
bobpursley
When you post serveral questions on the same post, without any work or indication of what you need, your chances go down.
a. Tension=mass*velocity^2/r
and your teacher is just too easy with this hint: (V=2(pie)r/T)
b. vix=speed*cosTheta
vertical speed=speed*sinTheta
c.time to fall:
h=1/2 g t^2
t= sqrt (2*1.8/9.8)
range=2t*7.2 m
d. time to fall:
50=1/2 g t^2
t= sqrt(100/9.8)
distance= 30m/s * time
a. Tension=mass*velocity^2/r
and your teacher is just too easy with this hint: (V=2(pie)r/T)
b. vix=speed*cosTheta
vertical speed=speed*sinTheta
c.time to fall:
h=1/2 g t^2
t= sqrt (2*1.8/9.8)
range=2t*7.2 m
d. time to fall:
50=1/2 g t^2
t= sqrt(100/9.8)
distance= 30m/s * time
Physics
So for the first one I got 0.78.
The second 23 horizontal and 20 vertical.
The third I got 8.64
And fourth I got 96
??
The second 23 horizontal and 20 vertical.
The third I got 8.64
And fourth I got 96
??