Question
kinsey leaves her house to exercise and run straight down a long street for 5.00 meters at a constant rate of 3m/s then turns and run back toward her house for 2 meters what is her average speed in m/s what is her displacement what is her average velocity in m/s
Answers
Henry
d = r*t.
5+2 = 3*t, t = 2.33 s.
r = d/t = 7m/2.33s. = 3 m/s.
Disp. = 5-2 = 3 m.
V = D/t = 3m/2.33s. = 1.29 m/s.
5+2 = 3*t, t = 2.33 s.
r = d/t = 7m/2.33s. = 3 m/s.
Disp. = 5-2 = 3 m.
V = D/t = 3m/2.33s. = 1.29 m/s.