Question

If Anna leaves her house at 11:00am and walks to her friends house located 1.34 miles away at 5 miles an hour walking speed, approximately what time will she get there?‎
t = d/V = 1.34mi/5mi/h = 0.268 h. =16
min.

Arrival time = 11:00AM + 16 mi 11:16AM.

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