Asked by Dam
Madison leaves her house and bikes north at a
constant speed of 10 miles per hour. If her dad
leaves the same house two hours later, driving
north at a constant speed of 15 miles per hour, how
long will it take him, in hours, to reach Madison?
constant speed of 10 miles per hour. If her dad
leaves the same house two hours later, driving
north at a constant speed of 15 miles per hour, how
long will it take him, in hours, to reach Madison?
Answers
Answered by
bobpursley
distanceMad=10*time
distanceDad=15(time-2)
set them equal, solve for time (the time Madison biked). His time is two hours less than that.
distanceDad=15(time-2)
set them equal, solve for time (the time Madison biked). His time is two hours less than that.
Answered by
Henry
d1 = V1 * (2+ t) = Distance Madison traveled.
d2 = V2 * t = Distance dad traveled.
When dad catches up, his distance will be equal to Madison's distance:
d1 = d2.
V1(2+t) = V2*t.
10(2+t) = 15t,
t = ?.
d2 = V2 * t = Distance dad traveled.
When dad catches up, his distance will be equal to Madison's distance:
d1 = d2.
V1(2+t) = V2*t.
10(2+t) = 15t,
t = ?.
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