Asked by Katie
The length of a rectangle exceeds twice its width by 4 feet.
If the area of the rectangle is 286 square feet, find the dimensions.
If the area of the rectangle is 286 square feet, find the dimensions.
Answers
Answered by
Reiny
width --- x
length --- 2x+4
x(2x+4) = 286
2x^2 + 4x - 286 = 0
x^2 + 2x - 143 = 0
(x+13)(x-11) = 0
x = 11 or x = -13, the last part is not possible
the width is 11, the length is 26
check:
26 is 4 more than twice 11
area = 11(26) = 286
length --- 2x+4
x(2x+4) = 286
2x^2 + 4x - 286 = 0
x^2 + 2x - 143 = 0
(x+13)(x-11) = 0
x = 11 or x = -13, the last part is not possible
the width is 11, the length is 26
check:
26 is 4 more than twice 11
area = 11(26) = 286
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.