Asked by Anonymous
Find the slope of x^2-16xy+y^2=1 at (1,1).
Is this -1?
Is this -1?
Answers
Answered by
Steve
2x - 16y - 16xy' + 2yy' = 0
at (1,1)
2-16-16y'+2y' = 0
y' = 14/-14 = -1
you are correct. However, (1,1) is not on the graph. ??
at (1,1)
2-16-16y'+2y' = 0
y' = 14/-14 = -1
you are correct. However, (1,1) is not on the graph. ??
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.