Asked by JOY

A bullet is fired in a horizontal direction with a muzzle velocity of 300m\s in the absence of air resistance,how far will it have dropped in travelling a horizontal distance of (a)20m (b)40m (c)60m (d)how far will it drop in one second

Answers

Answered by karen
In 20m that is 60s 40m is 7.5s 60m is 50s in one second is 300m
Answered by Henry
a. Dx = Xo*t. t = Dx/Xo = 20/300 = 0.067 s.
Dy = 0.5g*t^2 = 4.9*0.067^2 = 0.022 m.

b. t = d/Vo = 40/300 = 0.133 s.
Dy = 4.9*0.133^2 = 0.087 m.

c. t = Dx/Vo = 80/300 = 0.267 s.
Dy = 4.9*0.267^2 = 0.348 m.

d. Dy = 4.9*1^2 = 4.9 m.



Answered by Nwankwo Nnaemeka
I don't understand
Please explain
Them
Answered by Samuel
(a) S = ut+1/2at² (a=0)
S=ut
t= s/u
t= 20/300
t= 0.067 sec

h= ut+1/2gt² ( u=0)
h= 1/2*5*(0.067)²
h= 0.022 m

(b)s should be equal to 40m
(c) S = 60m

(d) h=ut+1/2gt² (u=0)
h=1/2gt² (g=9.8 or 10)
h= 1/2*9.8*1
h= 4.9m ( if g=10, h=5m)
Answered by Anonymous
Tank u
Answered by Anonymous
Explain better please
Answered by Anonymous
Number b and c u did not explain them
Answered by Kingsley
How do you get 4.9
Answered by Anonymous
20×3=
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions