Question
A bullet is fired in a horizontal direction with a muzzle velocity of 300m/s.in the absence of air resistance,how far will it have droppped in travelling a horizontal distance of 20m.
Answers
bobpursley
how long did it take to get 20 m?
time=distance/velocity=20/300 sec
how far did it drop?
distance=1/2 g time^2
time=distance/velocity=20/300 sec
how far did it drop?
distance=1/2 g time^2
Anonymous
80ma
Anonymous
Pls I n don't understand d solution
Clinton
S=horizontal vel. × time
20=300×t
t=20/309
t=0.067
S=1/2at^2
S=0.5×10×0.00444
S=0.222m
20=300×t
t=20/309
t=0.067
S=1/2at^2
S=0.5×10×0.00444
S=0.222m
Ali
Thanks you so much for the answer I appreciate very much
Bukkie
How did you get 0.00444
Anonymous
Thanks so much for the answer
Tamilore
T^2=0.067*0.067=0.004444
Anonymous
Where did you see 0.5
Limrat
1/2 is the same as 0.5
Anonymous
Thank you so much you have helped me to solve my physics assignment