A bullet is fired in a horizontal direction with a muzzle velocity of 300m/s.in the absence of air resistance,how far will it have droppped in travelling a horizontal distance of 20m.

how long did it take to get 20 m?

time=distance/velocity=20/300 sec

how far did it drop?
distance=1/2 g time^2

80ma

Pls I n don't understand d solution

S=horizontal vel. × time

20=300×t
t=20/309
t=0.067
S=1/2at^2
S=0.5×10×0.00444
S=0.222m

Thanks you so much for the answer I appreciate very much

How did you get 0.00444

Thanks so much for the answer

T^2=0.067*0.067=0.004444

Where did you see 0.5

1/2 is the same as 0.5

Thank you so much you have helped me to solve my physics assignment