Assuming 100% dissociation, calculate the freezing point and boiling point of 2.45 m Na2SO4(aq). Constants may be found here sites. google. com/site/chempendix/colligative.

Answer 1

for f.p.
delta T =i*Kf*m
i = 3 for Na2SO4
m you have
look up Kf. Subtract delta T from 0 C to find new f.p.

for b.p.
delta T = i*Kb*m
look up Kb. You have m and i, add delta T to 100 C to find new boiling point.