delta T = i*Kf*m for freezing point, subtract 0 C - delta T.
i for Na2SO4 = 3
delta T = i*Kb*m for boiling point add delta T + 100 = ?
Assuming 100% dissociation, calculate the freezing point and boiling point of 2.44 m Na2SO4(aq)
1 answer
1 answer