Asked by Akle

Assuming 100% dissociation, calculate the freezing point and boiling point of 3.13 m SnCl4(aq).
Tf=?
Tb=?

My work: SnCl4 with 100% dissociation gives a van't hoff factor of 5, 1Sn 4+ ion and 4 Cl- ions

deltaT = i x Kf x m for freezing point = 5 x 0.51C/m x 3.13m = deltaTf
deltaT = i x Kb x m for boiling point = 5 x 1.81C/m x 3.13m = deltaTb
Kf for water = 0.51C/m
Kb for water = 1.82C/m
for new freezing point, 0 - deltaT
for new boiling point, 100 + deltaT

Is this right? Can you tell me your answer so I can compare it with mine. I have one more attempt. Thanks.
Answered by Akle
What is the answer for Tb and Tf??????? please help.
Answered by DrBob222
You have Kf and Kb reversed. Kf for H2O is 1.86 and Kb for water is 0.51.
There are no AI answers yet. The ability to request AI answers is coming soon!