Akle
This page lists questions and answers that were posted by visitors named Akle.
Questions
The following questions were asked by visitors named Akle.
In a constant-pressure calorimeter, 60.0 mL of 0.340 M Ba(OH)2 was added to 60.0 mL of 0.680 M HCl. The reaction caused the temperature of the solution to rise from 24.07 °C to 28.70 °C. If the solution has the same density and specific heat as water, wha...
13 years ago
I know I posted this question again but no one is really helping me. Can someone please help me as soon as possible. In a constant-pressure calorimeter, 60.0 mL of 0.340 M Ba(OH)2 was added to 60.0 mL of 0.680 M HCl. The reaction caused the temperature of...
13 years ago
DrBob222, I got an answer of 33 and 24.23 as the temperature but it is incorrect. I looked at your response to David and unfortunately it did not help me. Would you please take a look at this question and help me out. Thanks. If the heat from burning 5.80...
13 years ago
A solution of H2SO4(aq) with a molal concentration of 1.94m has a density of 1.119g/mL. What is the molar concentration of this solution? I got an answer of 2.17 M and it is incorrect..please help. My work: So Molar concentration = molal concentration * d...
13 years ago
Assuming 100% dissociation, calculate the freezing point and boiling point of 3.13 m SnCl4(aq). Tf=? Tb=? My work: SnCl4 with 100% dissociation gives a van't hoff factor of 5, 1Sn 4+ ion and 4 Cl- ions deltaT = i x Kf x m for freezing point = 5 x 0.51C/m...
13 years ago
Answers
The following answers were posted by visitors named Akle.
You can select more than one answer and I can't seem to figure it out.
13 years ago
I got an answer of 24.23 degrees celsius and it marked me wrong? Can someone please explain and tell me what they get.
13 years ago
I think it is only the first one, but it marked me wrong.
13 years ago
I solved it numerous times and it says I am getting the wrong answer. Could you help explain how to solve it and see what I am doing wrong please.
13 years ago
Also can you look it up as well thanks. I really appreciate it!
13 years ago
sorry i meant the second one. I put the second one and it marked me wrong. As well, I put the last two and it marked me wrong also.
13 years ago
Yes! It is right. Thank you for your help. I really appreciate it.
13 years ago
This is my work..... (18g) (4.184 J)(28.70-24.07) I get 350.95 then i divide it by 0.0340 and get 10322.17. Then I divide it by a 1000 and get 10.322... It is wrong. Can you take a look at my work and tell me what i did wrong and confirm the right answer...
13 years ago
This is my work..... (18g) (4.184 J)(28.70-24.07) I get 350.95 then i divide it by 0.0340 and get 10322.17. Then I divide it by a 1000 and get 10.322... It is wrong. Can you take a look at my work and tell me what i did wrong and confirm the right answer...
13 years ago
Thank you! It did and i found my error a minute before you posted this. Once again, I always appreciate your help DrBob222 :)
13 years ago
yeah i converted it. It was suppossed to be kj :]
13 years ago
I got an answer of 56.976. The answer is negative though since the reaction is exothermic. Other than that great explanation. Thank you so much. You are the best!!!! :]
13 years ago
Thanks so much! :] I understand my mistake!
13 years ago
What is the answer for Tb and Tf??????? please help.
13 years ago