Asked by Diksha
The position of particle moving along x axis is given as a function of time t as x=t^2-4t+7.the distance covered by the particle in first four second is(x is in metre and t is in second). Plzz answer fastly..plzz
Answers
Answered by
Henry
X = t^2-4t+7.
X = 4^2 - 4*4 + 7 =
X = 4^2 - 4*4 + 7 =
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