v(t) = s'(t) = 6t^2-14t
v(5) = 6(5)^2 - 14(5)
= 150-70 = 80
The position of a particle, s metres from the starting point, after t seconds, is defined by the function s(t) = 2t^3 - 7t^2 + 4
a) determine the velocity of the particle after t seconds
b) determine the velocity after 5 seconds
2 answers
thank you!