Question
The position of a particle is given by equation X(t)=2t^2 where t in second and X in metere. The average velocity during time interval from t=1 s to t=5 s is.......
Answers
Elena
v(ave) =distance travelled/time taken.
x1=2t²=2•1²= 2 m.
x2=2t²=2•5²= 50 m.
v(ave)=(50-2)/(5-1) =48/4=12 m/s.
x1=2t²=2•1²= 2 m.
x2=2t²=2•5²= 50 m.
v(ave)=(50-2)/(5-1) =48/4=12 m/s.