Asked by Jonathan
                The position of a particle on the x-axis at time t, t > 0, is s(t) = ln(t) with t measured in seconds and s(t) measured in feet. What is the average velocity of the particle for 1 ≤ t ≤ e?
a)1
b)e
c)e-1
d)1/(e-1)
            
        a)1
b)e
c)e-1
d)1/(e-1)
Answers
                    Answered by
            Damon
            
    s(1) = 0
s(e) = 1
so distance traveled in (e - 1) seconds is one foot
v = 1/(e-1) = .582 ft/s
d)
    
s(e) = 1
so distance traveled in (e - 1) seconds is one foot
v = 1/(e-1) = .582 ft/s
d)
                    Answered by
            yall tripping
            
    come on foo
answer the question
    
answer the question
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