vx = dx/dt = 18 t^2 -6 t =6t(3t-1)
that is 0 at
t = 0 and at t = 1/3
calculate x at t = 0 and at t = 1/3
then acceleration = 36 t - 6 = 6(6t-1)
calculate acceleration at whatever time
The position of a particle is given by the function x = ( 6 t^3 - 3 t^2 + 2) m, where t is in s.
(a) At what time or times is vx = 0 m/s? (Enter NONE for t2 if there is only one time.)
Smaller time, t1 =
Larger time, t2 =
(b) What are the particle's position and its acceleration at this time(s)? position at time t1 =
acceleration at time t1 =
position at time t2 =
acceleration at time t2 =
1 answer
1 answer