Asked by anon yo

A 100-watt light bulb radiates energy at a rate of 100 J/s. (The watt, a unit of power or energy over time, is defined as 1 J/s.) If all of the light emitted has a wavelength of 525 nm , how many photons are emitted per second?

okay so i do:
((6.626*10^-34)(3.00*10^3))/(5.25*10^-7)
and i got 3.7862 *10^-24 J
then
(100J/S)*(photons/3.7862 *10^-24 J)
i got = 2.641*10^20 photons/second

im doing this on mastering chemistry and its saying its wrong!!??? i don't understand where my mistake is.
Answered by bobpursley
okay so i do:
((6.626*10^-34)(3.00*10^3))/(5.25*10^-7)
and i got 3.7862 *10^-24 J
THAT IS ENERGY PER PHOTON.

then
energy/photon*numberphotons/sec=100J/sec
Number Photons/sec=100/3.7862 *10^-24=2.64117057e25
Answered by anon yo
yeah, thanks haha i was off by 10^5 ughhh thank you so much, though
Answered by Mary
Isn't the speed of light 3.0*10^8 though instead of 3.0*10^3?
Answered by rhonda
Hi, I have for a constant for c is 3.00 x 10^8 and for the denominator ( 5.25 x 10^-9) after I converted it from nm to m. why are you exponents different? thanks
Answered by steel man
they slow af
Answered by hi
ok so whats the answer :|
Answered by Koji
Hi, its 5.71x10(14) <3
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