Asked by Sandra

Physics: For a 225-watt bulb, the intensity I of light in lumens at a distance of x feet is I=225/x^2.
a. What is the intensity of light 5 ft from the bulb?
b. Suppose your distance from the bulb doubles. How does the intensity of the light change? Explain.
Answered by bobpursley
a. what is 225/5^2 ?

b. doubles? then it must be .5^2 as much, or 25 percent, or 1/4

Answered by Sandra
That helps, thanks.
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