Ask a New Question

Question

csc theta = sqr root of 5, what is cot theta?
9 years ago

Answers

Steve
cot^2 = csc^2 - 1
9 years ago

Related Questions

secant theta = square root of seven over two and cosecant theta is less than zero r=8cos(theta)+5sin(theta), convert the polar equation into a rectangular equation and then complete... 3Square root of 2 cosine theta equals -1 tan theta= square root of 3 / 3 if o degrees is less than or equal to theta less than o equal to 360 2 cos(theta-13)= square root of 3 Xsin(theta)-Ysin(theta)=rootX^2+Y^2 andcos^2(theta)/a^2+sin^2(theta)/b^2 then find correct relation Xsin(theta)-Ysin(theta)=sqrtX^2+Y^2 and cos^2(theta)/a^2+sin^2(theta)/b^2=1/X^2+Y^2 then find correc... If csc theta = square root of 5 divided by 15, find sin theta csc theta = (sqr root 5) over 15, find sine theta 3cos^2(theta)-3 = 5sin(theta)-2
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use