Question
An arrow was fired horizontally from a platform above the ground. Exactly 3 sec after it was released, it struck the ground at an angle of 45o from the horizontal.
1) With what speed and from what height was it launched?
1) With what speed and from what height was it launched?
Answers
bobpursley
fired horizontally.
That means the horizontal speed at impace=vertical speed.
Vertical speed:
vf=9.8*3
so launch speed is that.
Now, platform height.
h=1/2 (9.8)3^2
That means the horizontal speed at impace=vertical speed.
Vertical speed:
vf=9.8*3
so launch speed is that.
Now, platform height.
h=1/2 (9.8)3^2