Question

An arrow is horizontally projected from the top of a tower with an initial velocity of 15m/s.if it reaches the ground 7seconds later,calculate the height of the tower (let g=10m/s0).

Answers

Enrique
x[f]=at^2/2+v[i]t+x[i]
Brackets dennote a subscript.
You're given x[f], a, t,and v[i]. You can just plug in their values into the formula and solve for x[i]. The horizontal velocity is irrelevant, the height of the tower is the initial position of the arrow, and final position is gonna be when it reaches the ground,or 0.
Henry
h = 0.5g*t^2.
Victor
245m
EMMANUEL
S=1/2*g*t*t, h=1/2*10*7*7 h=5*49=245m
Ify
H=1/2gt²
H=1/2×10×7²
H=1/2×10×49
H=1/2×490
H=245m

Related Questions