Question

An arrow is fired horizontally with a speed of 30ms-1 from a height of 2m above the ground level. Model the arrow as a particle which does not experience air resistance.
a)show that the time taken for the arrow
to hit the ground is 0.639 seconds correct to 3.s.f
b)find the horizontal distance travelled by the arrow
c)describe what happens during the flight of the arrow to the magnitude of:
i)the horizontal component of the velocity
ii)the vertical component of the velocity

please help im very confused give a very clear helpful explanation pplease so i can understand it

Answer 1

a. h = 0.5g*t^2.
h = 2 m, g = 9.8 m/s^2, t = ?.

b. d = Xo*t.
Xo = 30 m/s., t = Value from part a, d = ?.

c.
i. The horizontal component of velocity is initially 30 m/s and remains constant.

ii. The vertical component is initially 0 and increases as the arrow moves toward ground:

Y = Yo + g*t = 0 + 9.8*0.639 = 6.26 m/s. = Max vertical component reached.